🎄 - 2023 DAY 1 SOLUTIONS -🎄
🎄 - 2023 DAY 1 SOLUTIONS -🎄
Welcome everyone to the 2023 advent of code! Thank you all for stopping by and participating in it in programming.dev whether youre new to the event or doing it again.
This is an unofficial community for the event as no official spot exists on lemmy but ill be running it as best I can with Sigmatics modding as well. Ill be running a solution megathread every day where you can share solutions with other participants to compare your answers and to see the things other people come up with
Day 1: Trebuchet?!
Megathread guidelines
- Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
- Code block support is not fully rolled out yet but likely will be in the middle of the event. Try to share solutions as both code blocks and using something such as https://topaz.github.io/paste/ or pastebin (code blocks to future proof it for when 0.19 comes out and since code blocks currently function in some apps and some instances as well if they are running a 0.19 beta)
FAQ
- What is this?: Here is a post with a large amount of details: https://programming.dev/post/6637268
- Where do I participate?: https://adventofcode.com/
- Is there a leaderboard for the community?: We have a programming.dev leaderboard with the info on how to join in this post: https://programming.dev/post/6631465
🔒This post will be unlocked when there is a decent amount of submissions on the leaderboard to avoid cheating for top spots
🔓 Edit: Post has been unlocked after 6 minutes
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[Rust] 11157/6740
use std::fs; const m: [(&str, u32); 10] = [ ("zero", 0), ("one", 1), ("two", 2), ("three", 3), ("four", 4), ("five", 5), ("six", 6), ("seven", 7), ("eight", 8), ("nine", 9) ]; fn main() { let s = fs::read_to_string("data/input.txt").unwrap(); let mut u = 0; for l in s.lines() { let mut h = l.chars(); let mut f = 0; let mut a = 0; for n in 0..l.len() { let u = h.next().unwrap(); match u.is_numeric() { true => { let v = u.to_digit(10).unwrap(); if f == 0 { f = v; } a = v; }, _ => { for (t, v) in m { if l[n..].starts_with(t) { if f == 0 { f = v; } a = v; } } }, } } u += f * 10 + a; } println!("Sum: {}", u); }Started a bit late due to setting up the thread and monitoring the leaderboard to open it up but still got it decently quick for having barely touched rust
Probably able to get it down shorter so might revisit it
Oh, doing this is Rust is really simple.
I tried doing the same thing in Rust, but ended up doing it in Python instead.
Ive been trying to learn rust for like a month now and I figured I’d try aoc with rust instead of typescript. Your solution is way better than mine and also pretty incomprehensible to me lol. I suck at rust -_-
he used one letter variable names, it's very incomprehensible.
Get yourself thru the book and you'll get everything here.
Yeah tried to golf it a bit so its not very readable
Seems like the site doesn't track characters though so won't do that for future days
It basically just loops through every character on a line, if it's a number it sets last to that and if its not a number it checks if theres a substring starting on that point that equals one of the 10 strings that are numbers
In case that this might help.
h.chars() returns an iterator of characters. Then he concatenate chars and see if it's a digit or a number string.
You can swap match u.is_numeric() with if u.is_numeric and covert _ => branch to else.