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I bet someone knows an arithmetic topology where this is true.
Just redefine how you write multiplication
Actually, (sorry for that beginning) if we assume that these numbers are elements of the additive group of the integers (ℤ,+), some people define z^n for z∈ℤ and n∈ℕ as z+z+...+z}n-times
In mod 3 they're all 0.
39 comments