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Looks like n of a kind results in (n^2-n)/2 pairs. (Which is the same as the sum of 1...(n-1))
5 of a kind would be 10 pairs. 6 of a kind would be 15, etc
You're viewing a single thread.
Looks like n of a kind results in (n^2-n)/2 pairs. (Which is the same as the sum of 1...(n-1))
5 of a kind would be 10 pairs. 6 of a kind would be 15, etc